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             Example 23.     Divide 6x -   31x +  47  by 2x -  5 \  Quotient = 3x   - 8 and remainder = 7.
             and verify that Dividend = Divisor ´  Quotient
             + Remainder                                          Verification

             Solution:   Arranging the     dividend and the       Divisor ´ Quotient + Remainder
                                                                                                   5
                                                                                                      ´
             divisor in descending order of degree we get                                  = (2x  - ) (3x   - )  + 7
                                                                                                             8
                2
                              ¸
             (6x -  31x +  47 ) (2x -   ) 5                       = 2x ( 3x  - 8)  - 5 3x  - 8)  + 7
                                                                                    (
                              3x -  8                             = 6x  2  -16x  -15x  + 40  + 7
                                2
                      2x -  5  6x -  31x +  47                    = 6x  2  - 31x  + 47  = Dividend
                                  2
                              _6x m  15x                          Hence,
                                        _ 16x +  47                 Divisor ´ Quotient +Remainder
                                         _16x + 40                Hence verified.
                                         -
                                                       7
              E     xercise 6.3



             Divide the following:
                     3
                1. 6x  by 3x 2
                     4
                            3
                2. 6x -  24x - 15x 2  +  3 by (3x 2 )
                3. -12x  + 22x 2  -16x 3  + 4 by 2x
                     3
                4. (x -  by (x +1 )
                         ) 1
                                                            4
                                                                       2
                     2
                                                                 3
                            +
                5. (a +  12 a 35 ) by (a + 7 )        6. (2x +  x - 27x -  36x +  155 ) by (2x -  ) 5
                                                          2
                             2
                       3
                7. (2m -  5m +  8m -   ) 5  by (2m -  ) 3  8. (x -  7 xy 18 y 2  ) by (x -9  ) y
                                                                  -
                      3
                9. (9x + 6x +  ) 1  by (3x +  ) 1
               10. Divide and in each case verify the rela tion ®
                   Divi dend = Divi sor ´ Quotient ´ Remain der
                           3
                                                                                2
                                                                          3
                                 2
                    (i) (6x +  5x +  ) 4  by (2x +  ) 1             (ii) (9a +  3a -  5a +  ) 7  by (3a -  ) 1
             Standard Identities.                                        Proof: (a +  b ) (a -  ) b
                                                                                                          (
                                                                                               (
             There are some important Identities that must                                 = a a  - b)  + b a  - b)
             be remembered while working with algebraic                                    = a 2  - ab  + ab  - b 2
             expressions. These Identities makes our                                       = a 2  -b 2
             calculation much easier and faster.                    Identity 4. (x +  a ) (x +  ) b =  x +  (a +  ) b x +  ab
                                                                                                  2
                                        2
               Identity 1. (a +   ) b  2  =  a + 2 ab +  b 2             Proof: (x +  a ) (x +  ) b
                Proof: (a +    ) b  2  =  (a +  b ) (a +  ) b                              = (x  + )x  + (x  + )b
                                                                                                             a
                                                                                                  a
                                      = a a  + b)  + b a  + b)                             = x 2  + ax  + bx  + ab
                                          (
                                                     (
                                      = a 2  + ab  + ab  + b 2                             = x 2  + a  + b x  + ab
                                                                                                         )
                                                                                                  (
                                             2
                                      = a 2  + ab  + b 2                                   = x 2  + (algebraic sum
                                        2
               Identity 2. (a -   ) b  2  =  a - 2 ab +  b 2      of a and b) ´ + (the product of a and b).
                   Proof: (a -    ) b  2  = (a -  b ) (a -  ) b   Uses of Identities
                                          (
                                      = a a  - b)  - b a  - b)
                                                     (
                                                                  Identities are used in solving problems
                                      = a 2  - ab  - ab  + b 2    involving binomial expressions as they give us
                                      = a 2  - ab  + b 2          convenient way. Observe the use of identities
                                             2
                                              2
               Identity 3. (a +  b ) (a -  ) b =  a -  b 2        in these examples.
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                                                                                           Mathematics In Focus - 8
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