Page 53 - SM Class 5 Inner.cdr
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Word Problems
                                            1                                                             1
                    Example  9  :     Alka walks 2  km distance in one hour. How many kilometres can she walk in 8  hours?
                                            2                                                            4
                                                          1
                    Solution :   Distance walk in 1 hour = 2  km.
                                                          2
                                                           1             1     1
                               Distance can be walked in 8  hours    = 8   ´  2  km
                                                           4             4    2

                                                                                    ´
                                                                       33    5   33 5
                                                                     =     ´  =
                                                                                   ´
                                                                        4   2    4 2
                                                                       165       5
                                                                     =      =  20  km
                                                                        8        8

                                                 1                    1
                    Example 10 :    The cost of 5  kg of sugar is ` 95 . Find the cost of 1 kg sugar.
                                                 3                    4
                                                 1                 1
                    Solution :     The cost of 5  kg sugar = ` 95
                                                 3                 4
                                                              1     1
                                   Cost of 1 kg sugar   = 95    ¸  5
                                                             4     3
                                                                            +
                                                                        ´
                                                          95 4 +   1   5 3 1
                                                              ´
                                                        =            ¸
                                                               4          3
                                                           381   16
                                                        =      ¸
                                                            4    3
                                                           381   3
                                                        =      ´
                                                            4    16
                                                           1143
                                                        =
                                                           64
                                                               55
                                                        = ` 17
                                                               64
                                                                   55
                                   So the cost of 1 kg sugar is ` 17  .
                                                                  64


                                                                3              3                   2
                   Ex am ples 11 : Ranjan cov ered a dis tance of 20  km by bus, 12  km by train and  3  km
                                                                5              7                   5
                                 by car.  How much to tal dis tance did he cover?
                                                              3      3     2
                  Solution :    Total distance covered   = 20   + 12   + 3
                                                              5      7     5
                                                                          æ 3   3   2 ö
                                                        = (20  + 12  + )3  + ç  +  +  ÷
                                                                          è 5   7   5 ø
                                                                æ 3  ´ 7  + 3  ´ 5 2 7
                                                                               + ´ ö
                                                        = 35  + ç                     ÷
                                                                è         35          ø
                                                                21  + 15  + 14
                                                        = 35  +
                                                                    35




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