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2
                                                                                       2
                            2
             Example 8: 1  =1                                     Example 9:  (i) (11 -   (10 ) =  121
                                                                                      )
                                                                                              -
              2
                     3;
             2 = +  sum of first 2 odd numbers                                          = 121 100
                  1
              3
             3 = +   3 +  5 sum of first 3 odd numbers                                  = 21
                  1
              2
                   +
             4 =  1 3 +  5 +  7 sum of first 4 odd numbers                              = 11 10
                                                                                             +
              Prop erty  6: The difference of the square of              (ii)   (16 ) - (15 ) =  256 225 =  31
                                                                                          2
                                                                                   2
                                                                                                  -
                            two  con sec u tive  num bers  is
                                                                                                 +
                                                                                            =16 15
                            equal to the sum of the num bers.                      2       2
                                                                                                    -
                                       2
                            i.e. {(n +1 ) - n 2 }                        (iii)  (36 ) - (35 ) =  1296 1225 =  71
                                                                                                 +
                                                                                            = 36 35
                 = {(n  + + )(n   + - )} = {(n   + ) + }
                         1
                                       n
                                                   1
                                                       n
                            n
                                   1
              E     xercise 3.1
                1. Find which of the follow ing are perfect square:
                    (i) 121              (ii) 136                   (iii) 256              (iv) 441
                    (v) 76
                2. The follow ing numbers are not perfect squares. Give reasons?
                    (i) 257              (ii) 4592                  (iii) 2433             (iv) 5050
                    (v) 6098
                3. Find whether the square of the follow ing numbers are even or odd ?
                    (i) 431              (ii) 2826                  (iii) 8204             (iv) 17779
                    (v) 99998
                4. How many numbers lie between the square of the follow ing numbers
                    (i) 25; 26           (ii) 56; 57                (iii) 107;108
                5. Which of the follow ings are pythag o rean trip let:
                    (i) 30, 40, 50       (ii) 18, 80, 82            (iii) 15, 60, 65       (iv) 16, 63, 65
             Square Root                                          (i) Factorization Method
             The square root of a number x is that number         The square root of,    a perfect square number
             which when multiplied by itself gives x as the       can be found, by finding the prime factors of
             product.                                             the number and grouping them, in pairs.
                           2
                                                          2
                                                         )
               (i) 3 ´  3 =  3 =  9  (ii) (– 3) ´ (– 3) = (-3  = 9   Step I: Obtain the given number.
             Here 3 and (– 3) are the square roots of 9.            Step II: Re solve the given num ber into
             The symbol used for square root is                                prime fac tors by suc ces sive
                                                                               di vi sion.
              9 = ±3 ( read as plus or minus 3)
                                                                   Step III: Make pairs of prime factors such
             Considering only the positive root, we have  9 = 3
                                                                               that both the factors in each pair
              Note: Square of both pos i tive and neg a tive num ber           are same. Since the number is a
                                              2
              is a pos i tive num ber. Ex am ple: ( )3  = 3 ´ 3 = 9 and        perfect square, you will be able to
                  2
              (-3  = -3 ´ -3 = 9
                 )
                                                                               make an exact number of pairs of
                                                                               prime factors.
             Finding Square Root
                                                                   Step IV: Take one factor from each pair.
             To find a square root of a number, we have the
                                                                    Step V: Find the product of factors
             following three methods.
                                                                               obtained in step IV.
             (i) Factorization Method (ii) Long Division Method
                                                                   Step VI:   The product obtained in step V is
             (iii) Repeated Subtraction Method
                                                                               the required square root.
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                                                                                           Mathematics In Focus - 8
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