Page 19 - SM Class 5 Inner.cdr

E xercise 2.2

1. Subtract the following :
a. 334401 from 3138507 b. 162768 from 1,52,00,32
c. 9899 from 32415 d. 3089099 from 7400097

e. 431062 from 1552385 f. 5598762 from 9842343
g. 61045 from 9638055 h. 9845656 from 41553247

2. From the sum of 32,64,190 and 57,42,354, subtract 38,24,756

3. Find the missing digits :
a. b.
C TL L TTh Th H T O C TL L TTh Th H T O

7 7 0 0 3 6 0 4 4 0 9 0 6 0 4 2
– 0 0 2 1 0 0 1 3 – 2 3 0 5 0 1 0 0

9 4 6 3 0 4 1 0 0 2 2 3 4 0 2 0

Word Problems on adding and subtracting of large numbers

TL L TTh Th H T O
Example 7 : The population of Ahmadabad in 2014 was 9064506 and
9 0 6 4 5 0 6
next year it is increased by 98897. What was the
population of Ahmadabad in the year of 2015 ? + 9 8 8 9 7
Solution : Add the population of Ahamdabad in 2014 to 9 1 6 3 4 0 3
Increased population by next year =
= Total population of Ahmadabad in 2015
Therefore, the population Ahmadabad in the year of 2015
is 9163403.

TL L TTh Th H T O
Example 8 : Aarav bought a house for ` 1668000 and a shop for
` 0 1 6 6 8 0 0 0
` 2454000. How much did he spend in all?
` + 2 4 5 4 0 0 0
Solution : Cost of house = ` 1668000
Cost of shop = ` 2454000 ` 0 4 1 2 2 0 0 0
Total cost = ` 4122000
Amount of money spent in all ` 4122000.

C TL L TTh Th H T O
Example 9 : The sum of two numbers is 41482308. If one number is
4 1 4 8 2 3 0 8
3918695 then, find the other number.
– 3 9 1 8 6 9 5
Solution : Sum of two numbers = 41482308
One of the number = – 3918695 3 7 5 6 3 6 1 3

Second number = 37563613
Therefore, the other number is 37563613.

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Mathematics In Focus - 5