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(b)                                                     (ii) 0000086.  =   86     =  86  =   86
                                                                                                          ´
                       .38                    38 ´  10 - 1                          1000000     10 6   10 10   5
                                               .
                                               .
                       .038                   38 ´  10 - 2             =  86  ´10 -5  = 86 10 -5
                                                                                       .
                                                                                         ´
                      .0038                   38 ´  10 - 3               10
                                              .
                                               .
                     .00038                   38 ´  10 - 4        Ex am ple 10. Write the fol low ing num bers in
                     .000038                  38 ´  10 - 5        stan dard form
                                              .
                                               .
                    .0000038                  38 ´  10 - 6
                                                                     (i) Twenty six lakh    (ii) 725649
             We can say the following.                              (iii)  0.000772          (iv) 42012.5
               (i) To express any number in scientific            So lu tion :
                  notation, only one digit (other than 0) is to     (i) Twenty six lakh = 26 00 000,  ,
                  be kept on the left side of the decimal.                                                  6
                                                                                                =
                                                                        = 2.600000  ´1000000  2.6     ´  10
              (ii) In the scientific notation of a number less      (ii) 725646 =  7 25646 100000
                                                                                           ´
                                                                                   .
                  than 1, the index of 10 is        a negative                         5
                                                                                  ´
                                                                           .
                                                                        = 725646 10
                  integer and this integer is equal to the                           772     772
                                                                                              .
                                                                                      .
                  number of places the decimal moves to            (iii) 0000772.  =  10000  =  5
                  the right.                                                                 10
                                                                   (iv) 42012.5 =  4.20125 10000
                                                                                            ´
             (iii) In the scientific notation of the number
                  greater than 1, the index of 10 is a                   = 4.20125   ´10 4
                  positive integer and this index is equal to
                                                                  Ex am ple  11.    Write each of the following
                  the number of places the decimal moves
                  to the left.                                    num bers in the usual (i e. .  nor mal) form
                                                                     (i) 125 10.  ´  8     (ii) 22 10. ´  - 12
             Ex am ple 9. Ex press the fol low ing num bers in
                                                                                              125          125
                                                                                                       8
             sci en tific no ta tion :                            So lu tion : (i)  125 10.  ´  8  =  ´  10 =   ´ 10 8
                                                                                              100          10 2
               (i) 0.52                 (ii) 0.000086
                                                                                                   ´
                                    52     52   1           1                               =125 10    8  - 2
                                                      .
             So lu tion :  (i) 052.  =   =    ´    =  52 ´
                                    100   10    10        10 1                              =125 10    6
                                                                                                   ´
                             .
                          = 52 10  -1                                                       =12500000
                               ´
                 E       xercise 5.4
               1. Ex press the fol low ing as sin gle ex po nents.
                                                                         )
                 (a) ( )2 3 5             (b) (10 2 2            (c) (-3 4 5           (d) ( )p 2 3
                                                 )
                                                                             3                   6
                                                                     é æ  - ö 1  3  ù     é  2 æ ö 3  ù
                 (e) (-m  4 4             (f) (x a b             (g) ç ê  ÷ ú          (h) ç ÷ ú
                                                )
                           )
                                                                                          ê
                                                                     ê è 3  ø  ú          ê  9 è ø  ú û
                                                                                          ë
                                                                     ë
                                                                            û
                              n
                      é æ  pö m  ù
                 (i)  ê ç ÷ ú
                      ê è qø  ú û
                      ë
               2. Change the fol low ing neg a tive ex po nents into pos i tive ex po nents.
                                                                                              - 4
                                                                                            2 æ ö
                 (a) ( )12  - 3           (b) ( )-a  -2          (c) (100 ) - 5        (d) ç ÷
                                                                                            3 è ø
                           -9                    - b
                      æ  - ö 1                 x æ ö
                 (e) ç    ÷               (f)  ç ÷
                      è 10  ø                  y è ø
            54
                    Mathematics In Focus - 7
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